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6p^2-25p=0
a = 6; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·6·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*6}=\frac{0}{12} =0 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*6}=\frac{50}{12} =4+1/6 $
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